Integrand size = 35, antiderivative size = 43 \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\frac {2}{7} \left (a-\frac {c d^2}{e^2}\right ) (d+e x)^{7/2}+\frac {2 c d (d+e x)^{9/2}}{9 e^2} \]
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Time = 0.01 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.057, Rules used = {640, 45} \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\frac {2}{7} (d+e x)^{7/2} \left (a-\frac {c d^2}{e^2}\right )+\frac {2 c d (d+e x)^{9/2}}{9 e^2} \]
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Rule 45
Rule 640
Rubi steps \begin{align*} \text {integral}& = \int (a e+c d x) (d+e x)^{5/2} \, dx \\ & = \int \left (\frac {\left (-c d^2+a e^2\right ) (d+e x)^{5/2}}{e}+\frac {c d (d+e x)^{7/2}}{e}\right ) \, dx \\ & = \frac {2}{7} \left (a-\frac {c d^2}{e^2}\right ) (d+e x)^{7/2}+\frac {2 c d (d+e x)^{9/2}}{9 e^2} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.79 \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\frac {2 (d+e x)^{7/2} \left (9 a e^2+c d (-2 d+7 e x)\right )}{63 e^2} \]
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Time = 2.46 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.74
method | result | size |
gosper | \(\frac {2 \left (e x +d \right )^{\frac {7}{2}} \left (7 x c d e +9 e^{2} a -2 c \,d^{2}\right )}{63 e^{2}}\) | \(32\) |
pseudoelliptic | \(\frac {2 \left (e x +d \right )^{\frac {7}{2}} \left (7 x c d e +9 e^{2} a -2 c \,d^{2}\right )}{63 e^{2}}\) | \(32\) |
derivativedivides | \(\frac {\frac {2 c d \left (e x +d \right )^{\frac {9}{2}}}{9}+\frac {2 \left (e^{2} a -c \,d^{2}\right ) \left (e x +d \right )^{\frac {7}{2}}}{7}}{e^{2}}\) | \(39\) |
default | \(\frac {\frac {2 c d \left (e x +d \right )^{\frac {9}{2}}}{9}+\frac {2 \left (e^{2} a -c \,d^{2}\right ) \left (e x +d \right )^{\frac {7}{2}}}{7}}{e^{2}}\) | \(39\) |
trager | \(\frac {2 \left (7 c d \,e^{4} x^{4}+9 a \,e^{5} x^{3}+19 d^{2} e^{3} c \,x^{3}+27 a d \,e^{4} x^{2}+15 c \,d^{3} e^{2} x^{2}+27 a \,e^{3} d^{2} x +c \,d^{4} e x +9 a \,d^{3} e^{2}-2 c \,d^{5}\right ) \sqrt {e x +d}}{63 e^{2}}\) | \(99\) |
risch | \(\frac {2 \left (7 c d \,e^{4} x^{4}+9 a \,e^{5} x^{3}+19 d^{2} e^{3} c \,x^{3}+27 a d \,e^{4} x^{2}+15 c \,d^{3} e^{2} x^{2}+27 a \,e^{3} d^{2} x +c \,d^{4} e x +9 a \,d^{3} e^{2}-2 c \,d^{5}\right ) \sqrt {e x +d}}{63 e^{2}}\) | \(99\) |
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Leaf count of result is larger than twice the leaf count of optimal. 98 vs. \(2 (35) = 70\).
Time = 0.36 (sec) , antiderivative size = 98, normalized size of antiderivative = 2.28 \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\frac {2 \, {\left (7 \, c d e^{4} x^{4} - 2 \, c d^{5} + 9 \, a d^{3} e^{2} + {\left (19 \, c d^{2} e^{3} + 9 \, a e^{5}\right )} x^{3} + 3 \, {\left (5 \, c d^{3} e^{2} + 9 \, a d e^{4}\right )} x^{2} + {\left (c d^{4} e + 27 \, a d^{2} e^{3}\right )} x\right )} \sqrt {e x + d}}{63 \, e^{2}} \]
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Time = 0.88 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.23 \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\begin {cases} \frac {2 \left (\frac {c d \left (d + e x\right )^{\frac {9}{2}}}{9 e} + \frac {\left (d + e x\right )^{\frac {7}{2}} \left (a e^{2} - c d^{2}\right )}{7 e}\right )}{e} & \text {for}\: e \neq 0 \\\frac {c d^{\frac {7}{2}} x^{2}}{2} & \text {otherwise} \end {cases} \]
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none
Time = 0.19 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.88 \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\frac {2 \, {\left (7 \, {\left (e x + d\right )}^{\frac {9}{2}} c d - 9 \, {\left (c d^{2} - a e^{2}\right )} {\left (e x + d\right )}^{\frac {7}{2}}\right )}}{63 \, e^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 313 vs. \(2 (35) = 70\).
Time = 0.28 (sec) , antiderivative size = 313, normalized size of antiderivative = 7.28 \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\frac {2 \, {\left (315 \, \sqrt {e x + d} a d^{3} e + \frac {105 \, {\left ({\left (e x + d\right )}^{\frac {3}{2}} - 3 \, \sqrt {e x + d} d\right )} c d^{4}}{e} + 315 \, {\left ({\left (e x + d\right )}^{\frac {3}{2}} - 3 \, \sqrt {e x + d} d\right )} a d^{2} e + \frac {63 \, {\left (3 \, {\left (e x + d\right )}^{\frac {5}{2}} - 10 \, {\left (e x + d\right )}^{\frac {3}{2}} d + 15 \, \sqrt {e x + d} d^{2}\right )} c d^{3}}{e} + 63 \, {\left (3 \, {\left (e x + d\right )}^{\frac {5}{2}} - 10 \, {\left (e x + d\right )}^{\frac {3}{2}} d + 15 \, \sqrt {e x + d} d^{2}\right )} a d e + \frac {27 \, {\left (5 \, {\left (e x + d\right )}^{\frac {7}{2}} - 21 \, {\left (e x + d\right )}^{\frac {5}{2}} d + 35 \, {\left (e x + d\right )}^{\frac {3}{2}} d^{2} - 35 \, \sqrt {e x + d} d^{3}\right )} c d^{2}}{e} + 9 \, {\left (5 \, {\left (e x + d\right )}^{\frac {7}{2}} - 21 \, {\left (e x + d\right )}^{\frac {5}{2}} d + 35 \, {\left (e x + d\right )}^{\frac {3}{2}} d^{2} - 35 \, \sqrt {e x + d} d^{3}\right )} a e + \frac {{\left (35 \, {\left (e x + d\right )}^{\frac {9}{2}} - 180 \, {\left (e x + d\right )}^{\frac {7}{2}} d + 378 \, {\left (e x + d\right )}^{\frac {5}{2}} d^{2} - 420 \, {\left (e x + d\right )}^{\frac {3}{2}} d^{3} + 315 \, \sqrt {e x + d} d^{4}\right )} c d}{e}\right )}}{315 \, e} \]
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Time = 9.64 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.79 \[ \int (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right ) \, dx=\frac {2\,{\left (d+e\,x\right )}^{7/2}\,\left (9\,a\,e^2-9\,c\,d^2+7\,c\,d\,\left (d+e\,x\right )\right )}{63\,e^2} \]
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